What is the vertex of # y= –x^2 +12x – 4?

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Answer 1 · 2016-03-23T14:46:42

#color(blue)("Vertex"->(x,y)->(6,32)#

#color(blue)("General condition")#

Consider the standard form of #y=ax^2+bx+c)#

Write this as #y=a(x^2+b/ax)+c#

#x_("vertex")=(-1/2)xxb/a#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Solving your question")#

In your case #a= -1 and b=12 ->x_("vertex")=(-1/2)xx12/(-1) = +6#

Substitute #x=6 -> y_("vertex")=32#

#color(blue)("Vertex"->(x,y)->(6,32))#

Tony B