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What is the vertex of #y= -5x^2 + 8x - 13 #?

1 Answer

Jul 9, 2018

#x=4/5,y=-49/5#

Explanation:

We get

#y'(x)=-10x+8# (to find the vertex coordinates)
#y'(x)=0# if #x=4/5#

now we compute the #y# coordinate:

#f(4/5)=-5*(16)/(25)+8*4/5-13=(32-16-65)/5=-49/5#

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