What is the vertex of #y= 4(x-1)^2-1 #?
1 Answer
May 8, 2018
Explanation:
#"the equation of a parabola in "color(blue)"vertex form"# is.
#color(red)(bar(ul|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|))#
#"where "(h,k)" are the coordinates of the vertex and a"#
#"is a multiplier"#
#y=4(x-1)^2-1" is in this form"#
#"with "h=1" and "k=-1#
#rArrcolor(magenta)"vertex "=(1,-1)#
graph{4(x-1)^2-1 [-10, 10, -5, 5]}
