What is the vertex of y= 4(x-1)^2-1 ?
1 Answer
May 8, 2018
Explanation:
"the equation of a parabola in "color(blue)"vertex form" is.
color(red)(bar(ul|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|))
"where "(h,k)" are the coordinates of the vertex and a"
"is a multiplier"
y=4(x-1)^2-1" is in this form"
"with "h=1" and "k=-1
rArrcolor(magenta)"vertex "=(1,-1)
graph{4(x-1)^2-1 [-10, 10, -5, 5]}