What is the vertex of # y= 3x^2+8x-7#?

1 Answer
Binayaka C.
Apr 29, 2017

Vertex is at #(-1 1/3, -12 1/3)#

Explanation:

# y = 3x^2+8x-7# . Comparing with standard equation # y = ax^2+bx+c # we get here #a=3 , b=8 , c= -7#

x co-ordinate of vertex is # -b/(2a) or - 8/(2*3) = -4/3 = -1 1/3# .

Putting the value of #x= -4/3# we get y co-ordinate of vertex as

#y= 3* (-4/3)^2 +8*( -4/3) -7 = 16/3-32/3 -7=-16/3-7 =-37/3 = -12 1/3#

Vertex is at #(-1 1/3, -12 1/3)# [Ans]

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