What is the vertex of y=3x^2+6?

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What is the vertex of y=3x^2+6?

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Answer 1 · 2015-12-27T18:39:32

#(0,6)#

Explanation:

This is a 2nd degree quadratic function so its graph will be a parabola.
Such function of form #y=ax^2+bx+c# has turning point at #x=-b/(2a)#, so in this case at #x=0# which implies corresponding y-value is at the y-intercept itself of #6#.

Here is the graph as verification :

graph{3x^2+6 [-24.28, 40.64, -4.72, 27.74]}

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What is the vertex of y=3x^2+6?

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