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What is the vertex of # y= 2x^2-x-3-4(x-1)^2#?

1 Answer

May 1, 2018

#"Vertex": (7/4, -7/8)#

Explanation:

# y= 2x^2-x-3-4(x-1)^2#
#y = 2x^2-x-3-4x^2+8x-4#
#y = -2x^2 + 7x - 7#

#f(x) = ax^2 + bx + c " : x vertex" = (-b)/(2a)#

#(-b)/(2a) = (-7)/(2(-2) = 7/4#

#y = -2(7/4)^2 + 7(7/4) - 7 = (-7)/8#

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