What is the vertex of # y= 2x^2+5x-13-4(x-1)^2#?

Question

What is the vertex of # y= 2x^2+5x-13-4(x-1)^2#?

1 Answer

Impact of this question

1159 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-03T04:13:46

The vertex is #(13/4 , 33/8)#.

Explanation:

We expand and combine like terms:
#y = 2x^2-4x^2+5x+8x-13-4 = -2x^2+13x-17#
The x-coordinate of the vertex is:
#x = -\frac{b}{2a} = 13/4 = 3 1/4#
#y = 33/8 = 4 1/8#
Therefore, the vertex is #(13/4 , 33/8)#.

Science

Math

Humanities

... and beyond

What is the vertex of # y= 2x^2+5x-13-4(x-1)^2#?

1 Answer

Explanation:

Related questions

Impact of this question