What is the vertex of #y=-2x^2 - 2x -4 #?

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What is the vertex of #y=-2x^2 - 2x -4 #?

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Answer 1 · 2015-12-31T13:29:40

#(-1/2,7/2)#

Explanation:

First extract the common factor and then convert to vertex form by completing the square.
#y = -2(x^2 +x +2)#
#y=-2((x+1/2)^2 -1/4+2)#
#y = -2(x+1/2)^2 +7/2#
The vertex is #(-1/2,7/2)#

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What is the vertex of #y=-2x^2 - 2x -4 #?

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