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What is the vertex of #y= 2x^2 - 18x -6#?

1 Answer

Mar 2, 2016

#x_("vertex")=+9/2#
I will let you work out #y_("vertex")# by substitution

Explanation:

Write as:#" "y=2(x^2-18/2 x) -6#

Apply #" "(-1/2)xx(-18/2) = + 9/2#

#x_("vertex")=+9/2#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~
To derive #y_("vertex")# substitute #x=9/2# into the original equation and solve for y

Tony B

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