What is the vertex of # y^2-2y-2x+5=0#?

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Answer 1 · 2018-07-04T21:52:00

#(2, 1)#

Given equation:

#y^2-2y-2x+5=0#

#y^2-2y+1-1-2x+5=0#

#(y-1)^2-2x+4=0#

#(y-1)^2=2x-4#

#(y-1)^2=2(x-2)#

Above is the equation of horizontal parabola: #Y^2=4aX# which has

Vertex: #(X=0, Y=0)\equiv(x-2=0, y-1=0)\equiv(2, 1)#