What is the vertex of #y= 1/4(x+2)^2 - 9#?

1 Answer
Rachel
Mar 8, 2016

#(-2, -9)#

Explanation:

This problem is actually already set up in vertex form. From here, we have all the info we need.
#1/4(xcolor(green)(+)color(blue)(2))^2color(red)(-9)# tells us that the vertex is #(color(green)(-)color(blue)(2), color(red)(-9))#.

Notice that the sign switched for #color(blue)(2)#. But That's the only really "tricky" thing about thid type of problem. It Really is pretty easy. Just switch the sign for the #color(blue)(x)#-component, and leav the sign alone for the #color(red)(y)#-component.

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