What is the vertex form of #y= (x +6)(x/3 + 2) #?

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What is the vertex form of #y= (x +6)(x/3 + 2) #?

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Answer 1 · 2017-04-28T13:16:34

#y=1/3(x+6)^2#

Explanation:

First you need to expan this function
#y=1/3x^2+4x+12#
And then I need to make this function transform as this type
#y=a(x-h)^2+k#
So
#y=1/3(x^2+12x+36)+12-12#
Final
#y=1/3(x+6)^2#

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What is the vertex form of #y= (x +6)(x/3 + 2) #?

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