What is the vertex form of #y=(-x-2)(x+5)#?

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What is the vertex form of #y=(-x-2)(x+5)#?

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Answer 1 · 2017-11-28T00:19:33

#y=-(x+7/2)^2+9/4#

Explanation:

#y=-x^2-5x-2x-10#
#y=-x^2-7x-10#
To make it look more 'pretty': #y=-(x^2+7x+10)#
Now we need to make it into Vertex Form!
#y=-(x+7/2)^2+9/4#
Let's check by solving it.
#y=-(x+7/2)^2+9/4# =
#-(x^2+7x+49/4)+9/4# =
#-x^2-7x-49/4+9/4# =
#-x^2-7x-10#
That gets us back to our question. Therefore, we are correct!

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What is the vertex form of #y=(-x-2)(x+5)#?

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