What is the vertex form of #y=x^2+9x+28 #?

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Answer 1 · 2018-05-09T11:44:35

Vertex form of equation is # y = (x +4.5)^2 + 7.75#

# y = x^2 + 9 x +28# or

# y = (x^2+ 9 x +4.5^2) - 4.5^2+ 28# or

# y = (x +4.5)^2 - 20.25+ 28# or

# y = (x +4.5)^2 + 7.75# Comparing with vertex form of

equation #f(x) = a(x-h)^2+k ; (h,k)# being vertex we find

here #h= -4.5 , k=7.75 :.# Vertex is at #( -4.5,7.75) #

and vertex form of equation is # y = (x +4.5)^2 + 7.75#

graph{x^2+9 x+28 [-35.56, 35.56, -17.78, 17.78]} [Ans]