What is the vertex form of #y=x^2 - 9x + 2 #? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Nghi N. · mason m Nov 24, 2015 Find vertex form of #y = x^2 - 9x + 2# Ans: #y = (x - 9/2)^2 - 73/4# Explanation: Vertex #(x, y)#. #x#-coordinate of vertex: #x = (-b/(2a)) = 9/2# #y#-coordinate of vertex: #y = y(9/2) = (9/2)^2 - 9(9/2) + 2 = # #= 81/4 - 81/2 + 2 = -81/4 + 2 = -73/4# Vertex form --> #y = (x - 9/2)^2 - 73/4# Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 3412 views around the world You can reuse this answer Creative Commons License