What is the vertex form of #y= x^2+7x-2 #? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Shwetank Mauria Apr 14, 2017 Vertex form is #y=(x+7/2)^2-57/4# and vertex is #(-3 1/2,-14 1/4)# Explanation: #y=x^2+7x-2# = #x^2+2×7/2×x+(7/2)^2-(7/2)^2-2# = #(x+7/2)^2-49/4-2# = #(x+7/2)^2-57/4# Hence, vertex form is #y=(x+7/2)^2-57/4# and vertex is #(-7/2,-57/4)# or #(-3 1/2,-14 1/4)# Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 4514 views around the world You can reuse this answer Creative Commons License