What is the vertex form of #-y=x^2+4x+5#?

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What is the vertex form of #-y=x^2+4x+5#?

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Answer 1 · 2016-02-26T15:08:14

#y = (x + 2)^2 - 1.#

Explanation:

#y = - x^2 - 4x - 5#
x-coordinate of vertex:
#x = -b/(2a) = 4/(-2) = -2#
y-coordinate of vertex:
y(-2) = - 4 + 8 - 5 = -1
Vertex form: #y = (x + 2)^2 - 1#
graph{- x^2 - 4x - 5 [-10, 10, -5, 5]}

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What is the vertex form of #-y=x^2+4x+5#?

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