What is the vertex form of #y=x^2 + 3x - 10 #? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Binayaka C. Jul 30, 2016 In Vertex form: #y=(x+3/2)^2- 49/4# Explanation: #y=x^2+3x-10 = (x+3/2)^2-9/4-10=(x+3/2)^2- 49/4# Comparing with general vertex form #y=a(x-h)^2+k# we get vertex is at #(h,k)or (-3/2,-49/4)# graph{x^2+3x-10 [-40, 40, -20, 20]}[Ans] Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 5504 views around the world You can reuse this answer Creative Commons License