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What is the vertex form of #y=x^2-2x+8#?

1 Answer

Mar 24, 2018

Vertex form of equation is #y =(x-1)^2 +7#

Explanation:

#y=x^2-2x+8 or y=(x^2-2x+1)-1+8 # or

# y=(x-1)^2 +7 # Comparing with vertex form of

equation #f(x) = a(x-h)^2+k ; (h,k)# being vertex we find

here #h=1 , k=7, a=1 :.# Vertex is at #(1,7) #

and vertex form of equation is #y =(x-1)^2 +7#

graph{x^2-2x+8 [-35.54, 35.58, -17.78, 17.78]} [Ans]

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