What is the vertex form of #y=x^2-12x+6#?

1 Answer
Jim G.
Mar 9, 2016

#y = (x-6)^2 - 30#

Explanation:

The standard form of a quadratic function is #ax^2 + bx + c #

the equation # y = x^2 - 12x + 6 " is in this form " #

with a = 1 , b = -12 and c = 6

The vertex form is : #y = a (x-h)^2 + k #

where (h,k) are the coords of vertex

the x-coord of vertex ( h ) = #(-b)/(2a) = (12)/2 = 6#

and y-coord( k) = #6^2 - 12(6) + 6 = - 30#

now (h , k ) = (6 , -30) and a = 1

#rArr y = (x - 6)^2 - 30 " is vertex form "#

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