What is the vertex form of #y=5x^2-11 #?
1 Answer
May 30, 2016
#y=5x^2-11#
Explanation:
Though the equation is in the standard form.
Its vertex form is the same.
The vertex form of the equation can be written as
#y=a(x-h)^2+k#
Here
#a# is the co-efficient of#x^2#
Its vertex is#(0, -11)#
#a=5#
Then
#y=5(x-(0))^2-11#
#y=5x^2-11#
