What is the vertex form of #y= 4x^2 - 8x + 3 #?

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What is the vertex form of #y= 4x^2 - 8x + 3 #?

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Answer 1 · 2015-12-23T11:15:47

#y = 4(x-1)^2 -1#

Explanation:

Vertex form is #y = (ax +b)^2 +c# . In this case #a = 2# and #b = - 2#
#(2x -2)^2 = 4x^2 - 8x + 4# so we need to subtract 1
#y = (2x-2)^2 -1# which is better expressed as #y = 4(x-1)^2 -1#

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What is the vertex form of #y= 4x^2 - 8x + 3 #?

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