What is the vertex form of #y= 4x^2 + 10x + 6 #?
1 Answer
May 13, 2016
Explanation:
#y = 4x^2+10x+6#
#= 4(x^2+5/2x+3/2)#
#=4(x^2+2(x)(5/4)+(5/4)^2-(5/4)^2+6/4)#
#=4((x+5/4)^2-(5/4)^2+6/4)#
#=4(x+5/4)^2-25/4+24/4#
#=4(x+5/4)^2-1/4#
So:
#y = 4(x+5/4)^2-1/4#
Or we can write:
#y = 4(x-(-5/4))^2+(-1/4)#
This is in strict vertex form:
#y = a(x-h)^2+k#
with multiplier
