What is the vertex form of #y= 2x^2 + 5x - 3 #?

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Answer 1 · 2016-08-13T11:48:15

#"The form of equation is:"#

#y=2(x+5/4)^2-49/8#

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#y=ax^2+bx+c" Standard form"#

#y=a(x-h)^2+k" Vertex form"#

#P(h,k) "represents the coordinate of vertex"#

#y=2x^2+5x-3#

#a=2" ; "b=5" ; "c=-3)#

#h=-b/(2a)#

#h=-5/(2*2)=-5/4#

#k=2*(-5/4)^2+5*(-5/4)-3#

#k=2*25/16-25/4-3#

#k=50/16-25/4-3#

#k=(50-100-48)/16#

#k=-49/8=-6.13" Rounded the two decimal place"#

#"The form of equation is:"#

#y=2(x+5/4)^2-49/8#