What is the vertex form of #y=2x^2+3x-8#? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Binayaka C. Jul 27, 2017 Vertex form is # y = 2 (x + 3/4)^2 - 73/8 # Explanation: # y = 2x^2 +3x -8 or y = 2 (x^2+3/2x) -8 # or # y = 2 (x^2+3/2x + (3/4)^2 ) - 2*9/16-8 # or # y = 2 (x + 3/4)^2 - 9/8-8 # or # y = 2 (x + 3/4)^2 - 73/8 # Vertex is # (-3/4 , -9 1/8)# Vertex form is # y = 2 (x + 3/4)^2 - 73/8 # [Ans] Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 2443 views around the world You can reuse this answer Creative Commons License