What is the vertex form of #y=11x^2 - 4x + 31 #?

1 Answer
Binayaka C.
Oct 22, 2017

The vertex form of equation is #y= 11(x-2/11)^2 +30 7/11#
of which vertex is at #(2/11 , 30 7/11#)

Explanation:

# y= 11x^2-4x+31 or y= 11(x^2-4/11x) +31# or

#y= 11(x^2-4/11x +(2/11)^2)- 11*4/11^2 +31# or

#y= 11(x-2/11)^2- 4/11 +31# or

#y= 11(x-2/11)^2 +337/11# or

#y= 11(x-2/11)^2 +30 7/11#

The vertex form of equation is #y= 11(x-2/11)^2 +30 7/11#

of which vertex is at #(2/11 , 30 7/11#) [Ans]

Related questions
See all questions in Vertex Form of a Quadratic Equation
Impact of this question
1243 views around the world
You can reuse this answer
Creative Commons License