What is the vertex form of # f(x) = -x^2 -x-2 #?

1 Answer
Binayaka C.
May 18, 2017

The vertex form of equation is #f(x) = - (x+ 0.5)^2 -1.75#

Explanation:

#f(x)= - x^2-x-2 = - (x^2 +x) -2 = - (x^2 +x +(1/2)^2) +1/4-2#

#f(x)= - (x +1/2)^2 -7/4 or f(x) = - (x+ 0.5)^2 -1.75#

Comparing with general vertex form of equation,

#f(x) = a(x-h)^2+k ; (h,k) # being vertex, here vertex is at # (-0.5 , -1.75)#

The vertex form of equation is #f(x) = - (x+ 0.5)^2 -1.75# [Ans]

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