What is the vertex form of #5y=3x^2 -2x +8#?

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What is the vertex form of #5y=3x^2 -2x +8#?

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Answer 1 · 2017-08-09T08:35:59

#(1/3, 23/15)#

Explanation:

#5y=3x^2-2x+8#
#5y=3[x^2-(2/3)x]+8#
#5y=3[x^2-(2/3)x+(1/3)^2]+8-1/3#
#5y= 3(x-1/3)^2+23/3#
#y=3/5(x-1/3)^2+23/15# => in the vertex form of:
#y=a(x-h)^2+k# => where #(h, k)# is the vertex, thus the vertex is:
#(1/3, 23/15)#

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What is the vertex form of #5y=3x^2 -2x +8#?

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