What is the vertex form of #3y = 5x^2+5x-12#? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Binayaka C. Apr 19, 2016 #y=5/3(x+1/2)^2-53/12# Explanation: #y=5/3*x^2+5/3*x-4=5/3(x^2+x+1/4)-5/12-4=5/3(x+1/2)^2-53/12# Vertex is at #(-1/2,-53/12)# graph{5/3x^2+5/3x-4 [-10, 10, -5, 5]}[Ans] Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 1149 views around the world You can reuse this answer Creative Commons License