What is the value of the discriminant for the quadratic equation $7r^2 -14r + 10 = 0$ ?

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Answer 1 · 2018-06-07T18:55:50

$-84$

For any quadratic of the form

$ar^2+br+c$ ,

the discriminant is equal to

$b^2-4ac$

In our quadratic, we know that $a=7, b=-14$ and $c=10$ , so let's just plug these values into the value for the discriminant. We get

$(-14)^2-4(7)(10)$

which simplifies to

$196-4(70)$

$=>196-280=color(blue)(-84)$

Therefore, the value of our discriminant is equal to

$color(blue)(-84)$

Hope this helps!

What is the value of the discriminant for the quadratic equation 7r^2 -14r + 10 = 07r^2 -14r + 10 = 0?