What is the value of $3 {(3 - 1)}^{5} + {(\frac{1}{2})}^{2}$ $3(3-1)^5+(1/2)^2$ ?

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Answer 1 · 2017-01-04T02:46:56

See the step by step calculation below

First handle the two terms in parenthesis:

$3 {(3 - 1)}^{5} + {(\frac{1}{2})}^{2} =$ $3(color(red)(3 - 1))^5 + (color(blue)(1/2))^2 =$

$3 {(2)}^{5} + (\frac{1}{2} \times \frac{1}{2}) =$ $3(color(red)(2))^5 + (color(blue)(1/2 xx 1/2)) =$

$3 (2 \times 2 \times 2 \times 2 \times 2) + \frac{1}{4} =$ $3(color(red)(2 xx 2 xx 2 xx 2 xx 2)) + color(blue)(1/4) =$

$(3 \times 32) + \frac{1}{4} =$ $(3 xx color(red)(32)) + color(blue)(1/4) =$

$96 + \frac{1}{4} =$ $96 + 1/4 =$

$96 + 0.25 =$ $96 + 0.25 =$

$96.25$ $96.25$

What is the value of 3(3-1)^5+(1/2)^23(3−1)5+(12)23(3-1)^5+(1/2)^2?