What is the unit vector that is normal to the plane containing $(- 3 i + j -k)$ and $(2i+ j - 3k)$ ?

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What is the unit vector that is normal to the plane containing $(- 3 i + j -k)$ and $(2i+ j - 3k)$ ?

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Answer 1 · 2016-02-04T15:35:43

$C=-2i-11j-5k$

Explanation:

$A=-3i+j-k$
$B=2i+j-3k$
$C=A X B$
$"cross product A X B is normal to the plane"$
$"C is normal to the plane"$
$C=i(-3*1-(-1*1))-j((-3*-3)-(-1*2))+k(-3*1-2*1)$
$C=i(-3+1)-j(9+2)+k(-3-2)$
$C=-2i-11j-5k$

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What is the unit vector that is normal to the plane containing $(- 3 i + j -k)$ and $(2i+ j - 3k)$ ?

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Explanation:

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Math

Humanities

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What is the unit vector that is normal to the plane containing (- 3 i + j -k)(- 3 i + j -k) and (2i+ j - 3k)(2i+ j - 3k)?

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Explanation:

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What is the unit vector that is normal to the plane containing $(- 3 i + j -k)$ and $(2i+ j - 3k)$ ?