What is the the vertex of #y =x^2+4x-7 #?
1 Answer
Jan 10, 2016
Complete the square to find the vertex:
#(-2, -11)#
Explanation:
Complete the square:
#y = x^2+4x-7#
#= x^2+4x+4-11#
#= (x+2)^2-11#
This is an upright parabola with vertex at
graph{ x^2+4x-7 [-18.61, 13.43, -12.75, 3.28]}
