What is the the vertex of y =-x^2 - 4x - 10?

1 Answer
May 27, 2016

The vertex is at the point (-2,-6)

Explanation:

The equation of the parabola is given by:

y=a(x-h)^2+k

The vertex of the parabola is at the point (h,k)

Rearrange the equation y=-x^2-4x-4-6

y=(-x^2-4x-4)-6
y=-(x^2+4x+4)-6
y=-(x+2)^2-6
y=-(x-(-2))^2-6

h=-2 " and " k=-6

Vertex is at (-2,-6)

graph{-x^2-4x-10 [-6.78, 3.564, -9.42, -4.25]}