What is the the vertex of #y =-x^2 - 4x - 10#?

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Answer 1 · 2016-05-27T17:14:28

The vertex is at the point (-2,-6)

The equation of the parabola is given by:

#y=a(x-h)^2+k#

The vertex of the parabola is at the point #(h,k)#

Rearrange the equation #y=-x^2-4x-4-6#

#y=(-x^2-4x-4)-6#
#y=-(x^2+4x+4)-6#
#y=-(x+2)^2-6#
#y=-(x-(-2))^2-6#

#h=-2 " and " k=-6#

Vertex is at #(-2,-6)#

graph{-x^2-4x-10 [-6.78, 3.564, -9.42, -4.25]}