What is the the vertex of #y =-x^2-3x-6 #? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer Mark D. Apr 10, 2018 #(-3/2,-3/2)# Explanation: #(-b)/(2a)# is the #x# coordinate at this point #(--3)/(2xx-1)# =#3/(-2)# Put this value into the equation to find the #y# value #(-3/(-2))^2-3xx(3/(-2))-6# = #9/4+9/4-6#= #18/4-6# =#-3/2# Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph #y=x^2-2x+3#? How do you know if #y=16-4x^2# opens up or down? How do you find the x-coordinate of the vertex for the graph #4x^2+16x+12=0#? See all questions in Quadratic Functions and Their Graphs Impact of this question 3879 views around the world You can reuse this answer Creative Commons License