What is the the vertex of #y = 6(x - 2)^2 ­- 8#?

1 Answer
Feb 25, 2016

#"Vertex"->(x,y)->(2,-8)#

Explanation:

Tony B

The equation in this vertex form gives you the value of x for the vertex.

Consider the -2 from #(x-2)#

Apply #(-1)xx(-2)=+2#

#color(blue)(x_("vertex")=+2)#

Substitute #x=2# into the equation to find #y_("vertex")#

#y_("vertex") = 6( 2-2)^2-8#

#y_("vertex") = 6(0)^2-8#

#color(blue)(y_("vertex") = -8#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

#color(green)("Vertex"->(x,y)->(2,-8)#