What is the the vertex of #y = 6(x - 2)^2 - 8#?

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Answer 1 · 2016-02-25T11:36:32

#"Vertex"->(x,y)->(2,-8)#

Tony B

The equation in this vertex form gives you the value of x for the vertex.

Consider the -2 from #(x-2)#

Apply #(-1)xx(-2)=+2#

#color(blue)(x_("vertex")=+2)#

Substitute #x=2# into the equation to find #y_("vertex")#

#y_("vertex") = 6( 2-2)^2-8#

#y_("vertex") = 6(0)^2-8#

#color(blue)(y_("vertex") = -8#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

#color(green)("Vertex"->(x,y)->(2,-8)#

What is the the vertex of #y = 6(x - 2)^2 ­- 8#?