What is the the value of z for which the area under the normal curve to the right of z is equal to 0.76?

Question

0.33?

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Answer 1 · 2017-08-24T08:34:26

$- 0.71$ $-0.71$

For $Z ~ N (0, 1)$ $Z" "~" "N(0,1)$

we require

$P (Z > z) = 0.76$ $P(Z>z)=0.76$

Two things need to be remembered:

So the $z$ $z$ value in this case will be negative $z$ $z$

Because $P (Z > - z) = P (Z < z)$ $P(Z> -z)=P(Z< z)$ .

i.e. to find $P (Z > z) = 0.76$ $P(Z>z)=0.76$ , find $P (Z < z) = 0.76$ $P(Z < z) = 0.76$ instead, by table lookup

which gives $z = 0.71$ $z=0.71$ to 2 decimal places

so

$P(Z>z)=0.76" "=>" "z=–0.71$