What is the temperature of 350 mL of gas at .85 atm if it has a volume of 920 mL at STP?

1 Answer
May 7, 2016

88.3K88.3K

Explanation:

Use the equation:

(P_1 * V_1)/(T_1) = (P_2*V_2)/T_2P1V1T1=P2V2T2

Where P_1P1 is the pressure at STP, T_1T1 is the temperature at STP and V_1V1 is 0.92L0.92L.

Substitute all the values in.

[(1 atm)(0.92L)]/(273K) = [(0.85atm)(0.35L)]/T_2(1atm)(0.92L)273K=(0.85atm)(0.35L)T2

(T_2)(0.92L)= (273K)(0.85atm)(0.35L)(T2)(0.92L)=(273K)(0.85atm)(0.35L)

(T_2)(0.92L)= 81.22(T2)(0.92L)=81.22

(T_2) = 88.3K(T2)=88.3K