What is the temperature of 350 mL of gas at .85 atm if it has a volume of 920 mL at STP?

Question

1806 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-07T02:47:56

#88.3K#

Use the equation:

#(P_1 * V_1)/(T_1) = (P_2*V_2)/T_2#

Where #P_1# is the pressure at STP, #T_1# is the temperature at STP and #V_1# is #0.92L#.

Substitute all the values in.

#[(1 atm)(0.92L)]/(273K) = [(0.85atm)(0.35L)]/T_2#

#(T_2)(0.92L)= (273K)(0.85atm)(0.35L)#

#(T_2)(0.92L)= 81.22#

#(T_2) = 88.3K#