A certain sample of gas has a volume of 0.452 L measured at 87°C and 0.620 atm. What is its volume at 1 atm and 0°C?

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Answer 1 · 2014-05-19T19:36:38

To solve this problem we would use the combined gas law.

The formula for the combined gas law is
#((P_i)(V_i))/T_i = ((P_f)(V_f))/T_f#

We begin by identifying the values for each of the variables and identifying the missing value.

#P_i# = 0.620 atm
#V_i# = 0.452 L
#T_i# = 87 C + 273 = 360 K

#P_f# = 1 atm
#V_f# = ???
#T_f# = 0 C + 273 = 273 K

#((0.620 atm)(0.452 L))/(360 K) = ((1 atm)(x))/(273 K)#

#((273 K)(0.620 atm)(0.452 L))/((360 K)(1atm)) = (x L)#

#x L = 0.212 L#

I hope this was helpful.
SMARTERTEACHER