What is the sum of the infinite geometric series with $a_{1} = 42$ $a_1=42$ and $r = \frac{6}{5}$ $r=6/5$ ?

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What is the sum of the infinite geometric series with $a_{1} = 42$ $a_1=42$ and $r = \frac{6}{5}$ $r=6/5$ ?

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Answer 1 · 2015-05-28T20:50:01

That is a tricky question because a geometric series converges only when $| r | < 1$ $abs(r)<1$ . Here we have $| r | = ∣ ∣ ∣ \frac{6}{5} ∣ ∣ ∣ = \frac{6}{5} = 1 \frac{1}{6} > 1$ $abs(r)=abs(6/5)=6/5=1 1/6 > 1$ .

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What is the sum of the infinite geometric series with $a_{1} = 42$ $a_1=42$ and $r = \frac{6}{5}$ $r=6/5$ ?

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What is the sum of the infinite geometric series with a_1=42a1=42a_1=42 and r=6/5r=65r=6/5?

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What is the sum of the infinite geometric series with $a_{1} = 42$ $a_1=42$ and $r = \frac{6}{5}$ $r=6/5$ ?