What is the geometric power series? Precalculus Series Convergence of Geometric Series 1 Answer Bill K. Dec 7, 2015 a+ax+ax^{2}+ax^{3}+cdots, which converges to a/(1-x) when |x|<1. More generally, you could also write a+a(x-c)+a(x-c)^{2}+a(x-c)^{3}+cdots, which converges to a/(1-(x-c))=a/((1+c)-x) when |x-c| < 1. Answer link Related questions What are some examples of infinite geometric series? How can I tell whether a geometric series converges? How do I write a repeating decimal as an infinite geometric series? Can a repeating decimal be equal to an integer? How do I find the sum of the infinite geometric series 2/3, - 4/9, ...? How do I find the sum of the infinite geometric series such that a_1=-5 and r=1/6? What is the sum of the infinite geometric series with a_1=42 and r=6/5? What is the sum of the infinite geometric series 8 + 4 + 2 + 1 +... ? What is the sum of the infinite geometric series 1 + 1/5 + 1/25 +... ? How do I find the sum of the infinite geometric series 1/2 + 1 + 2 + 4 +... ? See all questions in Convergence of Geometric Series Impact of this question 2573 views around the world You can reuse this answer Creative Commons License