What is the square root of 6 times the square root 2? Algebra Radicals and Geometry Connections Simplification of Radical Expressions 1 Answer Serena D. May 1, 2018 #2sqrt3# Explanation: #sqrta*sqrtb=sqrt(a*b)#, thus #sqrt6*sqrt2=sqrt(6*2)# #sqrt12 rarr# There is a perfect square (#4#) in this that can be taken out #sqrt(4*3)# #2sqrt3# Answer link Related questions How do you simplify radical expressions? How do you simplify radical expressions with fractions? How do you simplify radical expressions with variables? What are radical expressions? How do you simplify #root{3}{-125}#? How do you write # ""^4sqrt(zw)# as a rational exponent? How do you simplify # ""^5sqrt(96)# How do you write # ""^9sqrt(y^3)# as a rational exponent? How do you simplify #sqrt(75a^12b^3c^5)#? How do you simplify #sqrt(50)-sqrt(2)#? See all questions in Simplification of Radical Expressions Impact of this question 35531 views around the world You can reuse this answer Creative Commons License