What is the square root of 3/4?

Question

↳Redirected from "What is #log_e# of e?"

38989 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-28T05:10:43

#sqrt3/2#

Given: #sqrt(3/4)#.

Split into:

#=sqrt3/sqrt4#

Notice how #sqrt4=2#, so we get:

#=sqrt3/2#

In here, I only took the principal square root, as there'll always a negative one as well, in this case its #-sqrt3/2#.