What is the square root of #20/125#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer EZ as pi Mar 31, 2018 #2/5# Explanation: Simplify #(20/125)# first, as neither #20# nor #125# are perfect squares. #sqrt(20/125) = sqrt ((2xx2xxcancel5)/(5xx5xxcancel5))# #= 2/5# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 5152 views around the world You can reuse this answer Creative Commons License