What is the square root of 128? Algebra Radicals and Geometry Connections Simplification of Radical Expressions 1 Answer Konstantinos Michailidis Sep 13, 2015 It is #sqrt128=sqrt(2*64)=sqrt(2^6*2)=2^3sqrt2=8sqrt2# Answer link Related questions How do you simplify radical expressions? How do you simplify radical expressions with fractions? How do you simplify radical expressions with variables? What are radical expressions? How do you simplify #root{3}{-125}#? How do you write # ""^4sqrt(zw)# as a rational exponent? How do you simplify # ""^5sqrt(96)# How do you write # ""^9sqrt(y^3)# as a rational exponent? How do you simplify #sqrt(75a^12b^3c^5)#? How do you simplify #sqrt(50)-sqrt(2)#? See all questions in Simplification of Radical Expressions Impact of this question 1971 views around the world You can reuse this answer Creative Commons License