What is the solution set for $x^2 - 5x + 6 = 0$ ?

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Answer 1 · 2015-08-31T00:34:01

$x_(1,2) = (5 +- 1)/2$

For a general form quadratic equation

$color(blue)(ax^2 + bx + c = 0)$

you can determine its roots by using the quadratic formula

$color(blue)(x_(1,2) = (-b +- sqrt(b^2 - 4ac))/(2a))$

In your case, $a = 1$ , $b = -5$ , and $c = 6$ . This means that you have

$x_(1,2) = (-(-5) +- sqrt((-5)^2 - 4 * 1 * 6))/(2 * 1)$

$x_(1,2) = (5 +- sqrt(1))/2$

$x_(1,2) = (5 +- 1)/2$

The two roots will thus be

$x_1 = (5+1)/2 = color(green)(3)" "$ and $" "x_2 = (5-1)/2 = color(green)(2)$

What is the solution set for x^2 - 5x + 6 = 0x^2 - 5x + 6 = 0?