What is the solution set for x^2 + 2x + 10 = 0?

1 Answer
Aug 10, 2015

x =(-2+ sqrt( - 36))/ (2)
x =(-2- sqrt( - 36))/ (2)

Explanation:

Since ------- 2^2 - (4 xx1 xx 10) < 0, x has imaginary roots

x =(-b+- sqrt(b^2 - (4ac)))/ (2a)
x =(-2+- sqrt(2^2 - (4xx1xx10)))/ (2xx1)
x =(-2+- sqrt(4 - 40))/ (2)
x =(-2+ sqrt( - 36))/ (2)
x =(-2- sqrt( - 36))/ (2)