What is the slope of the line perpendicular to $y = \frac{5}{12} x - 2$ $y=5/12x-2$ ?

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Answer 1 · 2016-01-03T17:11:20

$- \frac{12}{5}$ $-12/5$

Lines that are perpendicular have slopes that are opposite reciprocals.

The slope of $y = \frac{5}{12} x - 2$ $y=5/12x-2$ is $\frac{5}{12}$ $5/12$ .

The opposite reciprocal of $\frac{5}{12}$ $5/12$ is $- \frac{1}{\frac{5}{12}} = - \frac{12}{5}$ $-1/(5/12)=-12/5$ .

What is the slope of the line perpendicular to y=5/12x-2 y=512x−2 y=5/12x-2 ?