# What is the slope of the line normal to the tangent line of #f(x) = x^3-sqrtx # at # x= 3 #?

##### 1 Answer

Jan 2, 2016

The slope of tangent can be found by taking the first derivative. The slope of the normal is the negative reciprocal of the slope of the tangent.

#### Explanation:

Slope of tangent

Slope of tangent at

Slope of tangent

Simplifying we get

The slope of normal would be the negative reciprocal of this value.

**Slope of normal**