# What is the slope of the line normal to the tangent line of #f(x) = sec^3x+sin(2x-(3pi)/8) # at # x= (11pi)/8 #?

##### 1 Answer

Jul 10, 2018

Slope of the normal is 1/0.8104=1.2339

#### Explanation:

Slope of the tangent is -0.8104

Slope of the normal is 1/0.8104=1.2339